MonthOfTheYear
Function MonthOfTheYear(const AValue: TDateTime): Word
Example
procedure ScriptEvent(var Value: variant);
var
InputValue: TDateTime;
begin
InputValue := EncodeDateTime(2026, 7, 18, 9, 30, 0, 0);
Value := MonthOfTheYear(InputValue); // 7
end;
Usage
MonthOfTheYear returns the decoded calendar month number as an exact alias of MonthOf.
Parameters
| Name | Type | Description |
|---|---|---|
AValue | TDateTime, const | Encoded date/time whose calendar month component is required. |
Returns
A Word from 1 through 12, identical to MonthOf(AValue).
Behaviour
- Results are identical to
MonthOffor every input. - The time-of-day and day-of-month fields do not affect the returned month.
- Valid pre-epoch values are decoded correctly.
- No locale or timezone conversion occurs.
Important usage notes
- Despite the
...OfTheYearname, the result is not a zero-based position and is not a count of months elapsed; January returns 1. - Invalid or non-finite input can raise during date decoding.
Usage notes
Use either alias according to the naming pattern that best communicates the surrounding expression.
Additional Technical Info
MonthOfTheYear returns the one-based calendar month number encoded in a TDateTime. It is an exact implementation alias of MonthOf, provided for consistency with the other ...OfTheYear entries.
The example is fictional, deterministic and source-reviewed. It was not executed by the documentation workflow.
Implementation
The DateUtils import binds directly to Delphi 37.0 System.DateUtils.MonthOfTheYear. The terminal consists of a direct call to MonthOf, which extracts the month through DecodeDate.
Side effects
None.
Errors
Date decode exceptions propagate unchanged from Delphi.
Performance and concurrency
Constant-time delegation and calendar decoding with no shared mutable state.
Related entries
MonthOfis the exact implementation target.MinuteOfTheYearis a zero-based position within the year, unlike this one-based component.
External references
Created 2026-07-15